Answer:
The solution is 4.93 molal
Explanation:
We assume that solution is aqueous.
We need to apply the colligative property of elevation of boiling point:
ΔT = Kb . m . i
ΔT = Boiling T° of solution - Boiling T° of pure solvent
110.1°C - 100°C = 10.1°C
Kb = 0.512 °C/m
m = molality → unknown
i = Van't Hoff factor (numbers of ions dissolved)
We assume 100 % dissociation: CoCl₃ → Co³⁺ + 3Cl⁻ i = 4
We have 1 mol of Co³⁺ + 3 moles of chlorides
We replace data → 10.1°C = 0.512°C/m . m . 4
10.1°C / (0.512 m/°C . 4) = m → 4.93
