Question

In introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant G uses lead spheres with masses of 1.40 kg and 14.0 g whose centers are separated by about 2.30 cm. Calculate the gravitational force between these spheres, treating each as a particle located at the center of the sphere.

Answer 1

Answer:

F=2.47*10^{-10} N

Explanation:

The gravitational force is calculated by using

$F=G\frac{M_1M_2}{r^2}$

G: Cavendish constant = 6.67*10^{-12}Nm^2/kg^2

r=2.30cm=0.023m

M1=1.4kg

M2=14.0g=0.014kg

By replacing we have

F=2.47*10^{-10} N

hope this helps!!

Answer 2

Answer:

The gravitational force F =2.47*10⁻⁹N

Explanation:

Given Data;

First mass m1 = 1.40kg

Second mass m2 = 14.0g = 14/1000 = 0.014kg

distance (r) = 2.30cm = 0.023m

Gravitational constant = 6.67* 10⁻¹¹N/m²kg²

gravitational force (F)?

For calculating the gravitational force, we use the formula;

F = (Gm₁m₂)/r²

Substituting into the formula, we have

F = (6.67 * 10⁻¹¹ * 1.40 * 0.014)/0.023²

   = 1.30732*10⁻¹²/5.29*10⁻⁴

   = 2.47*10⁻⁹N