Answer:
[tex]g=2406.8m/s^{2}[/tex]
Explanation:
firstly we have to find the frequency and then the angular frequency.
The frequency will be:
[tex]f=\frac{419}{60} \\f=6.98Hz[/tex]
The angular frequency is:
ω[tex]=2\pi f[/tex]
ω[tex]=2*\frac{22}{7} *6.98[/tex]
ω[tex]=43.88rad /sec[/tex]
Now we can apply simple pendulum relationship
ω[tex]=\sqrt{\frac{g}{l} }[/tex]
make g the subject of the formula
[tex]g=w^{2} l\\g=43.88^{2} *1.25\\g=2406.8m/s^{2}[/tex]