Question

The electric field on the surface of an irregularly shaped conductor varies from 66.0 kN/C to 26.0 kN/C. (a) Calculate the local surface charge density at the point on the surface where the radius of curvature of the surface is greatest. nC/m2 (b) Calculate the local surface charge density at the point on the surface where the radius of curvature of the surface is smallest. nC/m2

Answer 1

Answer:

Explanation:

We know that at pointed corner of a conductor , charge accumulate ie electric field is  maximum . Ar pointed corner , radius of curvature will be least . That is why charge leakage is greatest at pointed corner of a charged conductor.

a ) Electric field will be 26.0 kN/C at the point where radius of curvature is greatest .

b ) So electric field will be 66 kN /C at the point where radius of curvature is smallest .