Answer:
no solution
Step-by-step explanation:
[tex]\frac{1}{25} = 5^x+4\\\frac{-99}{4} = 5^x[/tex]
[tex]ln(\frac{-99}{4} ) = ln(5^x)\\ln(\frac{-99}{4} ) = xln(5)[/tex]
we can already see the fault in the equality. We cannot possibly log a negative value; negative values are not in the domain of the ln or log function.