Suppose that f(x)=x+2x−1 is differentiable and has an inverse for x>1 and f(3)=52. Find (f−1)′(52)Suppose that f(x)=x+2x−1 is differentiable and has an inverse for x>1 and f(3)=52. Find (f−1)′(52)+

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Answer:

[tex](f^{-1})'(x)[/tex] = 1/3

Step-by-step explanation:

[tex](f^{-1})'(x)[/tex] = [tex]\frac{1}{f'(f^{-1}(x))}[/tex]

if f(x) = y, [tex]f^{-1}(y)[/tex] = x, so

[tex]f^{-1}(52)[/tex] = 3 since f(3) = 52

finding f'(3)

f'(x) = 3

f'(3) = 3

[tex](f^{-1})'(x)[/tex] = 1/f'(x) = 1/3

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