Answer: The specific heat capacity of chromium is [tex]2010J/g^0C[/tex]
Explanation:
[tex]heat_{absorbed}=heat_{released}[/tex]
As we know that,
[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]
[tex]m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)][/tex] .................(1)
where,
q = heat absorbed or released
[tex]m_1[/tex] = mass of chromium = 15.5 g
[tex]m_2[/tex] = mass of water = 55.5 g
[tex]T_{final}[/tex] = final temperature =[tex]18.9^0C[/tex]
[tex]T_1[/tex] = temperature of chromium = [tex]100^oC[/tex]
[tex]T_2[/tex] = temperature of water = [tex]16.50^oC[/tex]
[tex]c_1[/tex] = specific heat of chromium= ?
[tex]c_2[/tex] = specific heat of water= [tex]4.184J/g^0C[/tex]
Now put all the given values in equation (1), we get
[tex]-15.5\times c_1\times (19.5-18.9)=[55.5\times 4.184\times (19.5-100)][/tex]
[tex]c_1=2010J/g^0C[/tex]
The specific heat capacity of chromium is [tex]2010J/g^0C[/tex]
