Respuesta :
Answer:
After 44year at interest rate of 6%
You will have $12,985.5 in your account
Explanation
Step one
Applying the compound interest formula we have A = P (1 + r/n)^nt
A = Final amount
r= nominal annual interest rate in percentage terms,
and n = number of compounding period
Where P = Principal
t= time in years
Given p=$1,000
n=44
r=6%
Step two
Inserting our given information
A=$1000 [(1 + 0.06/1)^44*1]
A=$1000 [(1.06)^44*1]
A=$1000*12.9854819127
A=$12,985.5
Answer:
$7368.96
Explanation:
For a Principal P invested at rate r over a period of n years.
[TeX] Amount \: at \: Compound \: Interest= P(1+r)^n [/TeX]
In the case above,
P=$1000
n=44 years
At Rate,r=4%=0.04
[TeX] Amount \: at \: Compound \: Interest= 1000(1+0.04)^{44} [/TeX]
[TeX] = 1000(1.04)^{44} [/TeX]
[TeX] = 5616.52 [/TeX] dollars
At Rate,r=6%=0.06
[TeX] Amount \: at \: Compound \: Interest= 1000(1+0.06)^{44} [/TeX]
[TeX] = 1000(1.06)^{44} [/TeX]
[TeX] = 12985.48 [/TeX] dollars
The difference at 6% instead of 4%
=12985.48-5616.52
=$7368.96