Answer:
The temperature of the steam at turbine exit is [tex]T_{2}[/tex] = 1190.26 K
Explanation:
Given data
[tex]T_{1} = 500[/tex]°c = 773 K
Mass flow rate = 3.2 [tex]\frac{kg}{s}[/tex]
Power output = 2.5 MW = 2500 KW
From steady flow energy equation
[tex]h_{1} + KE_{1} + PE_{1} + Q = h_{2} + KE_{2} + PE_{2} + W\\[/tex]
Since Kinetic & potential energy changes are negligible.
[tex]h_{1} + Q = h_{2} + W[/tex]
Since turbine is adiabatic so Q = 0
[tex]h_{1} = h_{2} + W[/tex]
[tex]h_{1} - h_{2} = W[/tex]
[tex]m C_{p} (T_{2} - T_{1} ) = W[/tex]
Put all the values in above equation
3.2 × 1.8723 × ( [tex]T_{2}[/tex] - 773 ) = 2500
[tex]T_{2}[/tex] - 773 = 417.26 K
[tex]T_{2}[/tex] = 1190.26 K
This is the temperature of the steam at turbine exit.