Answer: The mass of gold participated in the chemical reaction is 2.95 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Molar mass of gold = 197 g/mol
Moles of gold participated in the reaction = 0.015 moles
Putting values in above equation, we get:
[tex]0.015mol=\frac{\text{Mass of gold}}{197g/mol}\\\\\text{Mass of gold}=(0.015mol\times 197g/mol)=2.95g[/tex]
Hence, the mass of gold participated in the chemical reaction is 2.95 grams
