Assume that 25 percent of all business executives feel that the benefits of outsourcing are either less or much less than expected. What is the probability of observing a random sample of 1,000 randomly selected business executives with a sample proportion of 22 percent?

Respuesta :

Answer:

probability = 0.0026

Step-by-step explanation:

given data

random sample n = 1,000

benefits of outsourcing  p = 25 percent

sample proportion = 22 percent

solution

we know here

p = 0.25

and P(p1 = 0.22)

so P( X = 220)

and

P(219.5 < X < 220.5)

and here mean will be

mean = n × p

mean = 1000 × 0.25

mean = 250

and standard deviation will be

standard deviation SD = [tex]\sqrt{(npq)}[/tex]  

SD =  [tex]\sqrt{(1000\times 0.25\times 0.75)}[/tex]  

SD = 13.6930

and we know Z is

Z = [tex]\frac{(X - mean)}{SD}[/tex]  

so here

P(219.5 < X < 220.5)

probability = 0.0026

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