Answer: 1.2
Explanation:
pOH is the negative logarithm of hydroxide ion concentration in the solution.
Thus, pOH is expressed as
pH = - log(OH-)
NaOH(aq) ---> Na(aq) + OH-(aq)
The alkali ionizes to give hydroxide ion OH- as the only negative ion. Hence, the concentration of OH- is also 0.0768
So, pOH = - log(0 .0768)
pH = -(-1.15)
pH = 1.15 (since the two minus signs will cancel out)
Round the pOH value to the nearest tenth as 1.2
Thus, the pOH concentration of 0 .0768 NaOH solution is 1.2 (highly concentrated)
