Answer: The half cell reactions taking place at cathode and anode is written below.
Explanation:
Oxidation reaction occurs at anode and reduction reaction occurs at cathode. Here, magnesium is getting oxidized and aluminium is getting reduced.
The half reactions for the cell is:
Oxidation half reaction (anode): [tex]Mg(s)\rightarrow Mg^{2+}(aq.)+2e^-[/tex] ( × 3)
Reduction half reaction (cathode): [tex]Al^{3+}(aq.)+3e^-\rightarrow Al(s)[/tex] ( × 2)
Overall cell reaction: [tex]3Mg(s)+2Al^{3+}(aq.)\rightarrow 3Mg^{2+}(aq.)+2Al(s)[/tex]
Hence, the half cell reactions taking place at cathode and anode is written above.