Answer:
The flow speed at 2.6 cm diameter pipe is 1.2 [tex]\frac{m}{s}[/tex]
Explanation:
Given :
Speed at 4 cm diameter pipe [tex]v_{1} = 0.50 \frac{m}{s}[/tex]
Area of 4 cm diameter pipe [tex]A_{1} = \pi (2 \times 10^{-2} )^{2}[/tex]
[tex]A_{1} = 12.56 \times 10^{-4}[/tex][tex]m^{2}[/tex]
Area of 2.6 cm diameter pipe [tex]A_{2} = \pi (1.3 \times 10^{-2} )^{2}[/tex]
[tex]A_{2} = 5.306 \times 10^{-4} m^{2}[/tex]
From the equation of continuity,
[tex]A_{1} v_{1} = A_{2} v_{2}[/tex]
Find the speed at 2.6 cm diameter pipe,
[tex]v_{2} = \frac{A_{1} v_{1} }{A_{2} }[/tex]
[tex]v_{2} = \frac{12.56 \times 10^{-4} \times 0.50 }{5.306 \times 10^{-4} }[/tex]
[tex]v_{2} =1.2 \frac{m}{s}[/tex]
Therefore, the flow speed at 2.6 cm diameter pipe is 1.2 [tex]\frac{m}{s}[/tex]