Question

Six housing subdivisions within a city area are target for emergency service by a centralized fire station. Where should the new fire station be located such that the maximum rectilinear travel distance is minimized? Assume that the total value of the homes in each sub-division is equal. The centroid locations (in miles) are as follows:
Subdivsion x-coordinate y-coordinate Total Vaue (in millions)
A 20 15 50
B 25 25 120
C 13 32 100
D 25 14 250
E 4 21 300
F 18 8 75

Answer 1

Answer:

Explanation:

Since there are six points, the minimum distance from all points would be the centroid of polygon formed by A,B,C,D,E,F

To find the coordinates of centroid of a polygon we use the following formula. Let A be area of the polygon.

$C_{x}=\frac{1}{6A} sum(({x_{i} +x_{i+1})(x_{i}y_{i+1}-x_{i+1}y_{i}))$     where i=1 to N-1 and N=6

$C_{y}=\frac{1}{6A} sum(({y_{i} +y_{i+1})(x_{i}y_{i+1}-x_{i+1}y_{i}))$

A area of the polygon can be found by the following formula$A=\frac{1}{2} sum(x_{i} y_{i+1} -x_{i+1} y_{i})$ where i=1 to N-1

$A=\frac{1}{2}[ (x_{1} y_{2} -x_{2} y_{1})+ (x_{2} y_{3} -x_{3} y_{2})+(x_{3} y_{4} -x_{4} y_{3})+(x_{4} y_{5} -x_{5} y_{4})+(x_{5} y_{6} -x_{6} y_{5})]$

A=0.5[(20×25 -25×15) +(25×32 -13×25)+(13×21 -4×32)+(4×8 -18×21)+(18×14 -25×8)

A=225.5 miles²

Now putting the value of area in Cx and Cy

$C_{x} =\frac{1}{6A}[ [(x_{1}+x_{2})(x_{1} y_{2} -x_{2} y_{1})]+ [(x_{2}+x_{3})(x_{2} y_{3} -x_{3} y_{2})]+[(x_{3}+x_{4})(x_{3} y_{4} -x_{4} y_{3})]+[(x_{4}+x_{5})(x_{4} y_{5} -x_{5} y_{4})]+[(x_{5}+x_{6})(x_{5} y_{6} -x_{6} y_{5})]]$

putting the values of x's and y's you will get

$C_{x} =15.36$

For Cy

$C_{y} =\frac{1}{6A}[ [(y_{1}+y_{2})(x_{1} y_{2} -x_{2} y_{1})]+ [(y_{2}+y_{3})(x_{2} y_{3} -x_{3} y_{2})]+[(y_{3}+y_{4})(x_{3} y_{4} -x_{4} y_{3})]+[(y_{4}+y_{5})(x_{4} y_{5} -x_{5} y_{4})]+[(y_{5}+y_{6})(x_{5} y_{6} -x_{6} y_{5})]]$

putting the values of x's and y's you will get

$C_{y} =22.55$

So coordinates for the fire station should be (15.36,22.55)

Answer 2

In this exercise we have to use the knowledge of coordinates to calculate the points of coordinates X and Y, in this way we find that:

So coordinates will be  $15.36,22.55$

Since skilled happen a goal in football, the minimum distance from all points hopeful the centroid of closed plane figure make by A,B,C,D,E,F. To find the match of centroid of a closed plane figure we use the following recipe. Let A exist scope of a surface of the closed plane figure.

 $C_{x}=\frac{1}{6 A} \sum}\left(\left(x_{i}+x_{i+1}\right)\left(x_{i} y_{i+1}-x_{i+1} y_{i}\right)\right)$    where i=1 to N-1 and N=6

$C_{y}=\frac{1}{6 A} \sum}\left(\left(y_{i}+y_{i+1}\right)\left(x_{i} y_{i+1}-x_{i+1} y_{i}\right)\right)$

A area of the polygon can be found by the following formula:

$A=\frac{1}{2} \sum}\left(x_{i} y_{i+1}-x_{i+1} y_{i}\right) \ where\ i=1 \ to \ N-1$

$A=\frac{1}{2}\left[\left(x_{1} y_{2}-x_{2} y_{1}\right)+\left(x_{2} y_{3}-x_{3} y_{2}\right)+\left(x_{3} y_{4}-x_{4} y_{3}\right)+\left(x_{4} y_{5}-x_{5} y_{4}\right)+\left(x_{5} y_{6}-x_{6} y_{5}\right)\right]$

$A=0.5[(20*25 -25*15) +(25*32 -13*25)+(13*21 -4*32)+(4*8 -18*21)+(18*14 -25*8)$

$A=225.5 \ miles$

Now putting the value of area in Cx, we have:

$C_{x}=\frac{1}{6 A}\left[\left[\left(x_{1}+x_{2}\right)\left(x_{1} y_{2}-x_{2} y_{1}\right)\right]+\left[\left(x_{2}+x_{3}\right)\left(x_{2} y_{3}-x_{3} y_{2}\right)\right]+\left[\left(x_{3}+x_{4}\right)\left(x_{3} y_{4}-\right.\right.\right. \left.\left.\left.x_{4} y_{3}\right)\right]+\left[\left(x_{4}+x_{5}\right)\left(x_{4} y_{5}-x_{5} y_{4}\right)\right]+\left[\left(x_{5}+x_{6}\right)\left(x_{5} y_{6}-x_{6} y_{5}\right)\right]\right]$

Putting the values of x's and y's you will get

$C_{x}=15.36$

For Cy, we have that:

$C_{y}=\frac{1}{6 A}\left[\left[\left(y_{1}+y_{2}\right)\left(x_{1} y_{2}-x_{2} y_{1}\right)\right]+\left[\left(y_{2}+y_{3}\right)\left(x_{2} y_{3}-x_{3} y_{2}\right)\right]+\left[\left(y_{3}+y_{4}\right)\left(x_{3} y_{4}-\right.\right.\right. \left.\left.\left.x_{4} y_{3}\right)\right]+\left[\left(y_{4}+y_{5}\right)\left(x_{4} y_{5}-x_{5} y_{4}\right)\right]+\left[\left(y_{5}+y_{6}\right)\left(x_{5} y_{6}-x_{6} y_{5}\right)\right]\right]$

Putting the values of x's and y's you will get

$C_y= 22.55$

See more about coordinates at brainly.com/question/17514638