Question

Plzzzzzz help!!!!! For 25 points
#No wrong answers

Answer 1

Step-by-step explanation:

$y = -x + 3$

$y = -2x + 1$

To determine where these lines intersect, we can set the equations equal to each other and solve for $x$:

$y = -x + 3 = -2x + 1$

$-x + 3 = -2x + 1$

Let's move the terms with an $x$ variable to the left-hand side of the equation, and everything else to the right-hand side of the equation:

$2x - x = 1 - 3$

$x = -2$

Now that we know $x = -2$, we can plug this value into either equation to get the value for $y$:

$y = -x + 3$

$y = -(-2) + 3$

$y = 2 + 3$

$y = 5$

or

$y = -2x + 1$

$y = -2(-2) + 1$

$y = 4 + 1$

$y = 5$

Therefore, the solution to this system of equations is $(-2, 5)$

Answer 2

I'm solving it using substitution method:-

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Given,

y= -x+3

=>x+y=3

=>x=3-y-----------(1)

y=-2x+1

=>y+2x=1

=>y+2(3-y)=1 {putting the value of x from eqn 1}

=>y+6-2y=1

=>6-y=1

=>y=5

putting the value of y on eqn 1:-

x=>3-5=-2

Hence,x=-2,y=5

or,.

.

solution is (-2,5)

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