Answer:
The focal length of this lens is f = 0.55 D
Explanation:
Given that the far point of an eye ( d )= 180 cm = 1.8 m
We know that focal length of lens is given by
[tex]f = \frac{1}{d}[/tex]
Put the value of d in above equation we get
[tex]f = \frac{1}{1.8} \ m^{-1}[/tex]
f = 0.55 D
Therefore the focal length of this lens is f = 0.55 D