Given that the recursive formula for a sequence is [tex]a_n=a_{n-1}+2n[/tex]
The first term of the sequence is [tex]a_1=4[/tex]
We need to determine the first four terms of the sequence.
Second term:
The second term of the sequence can be determined by substituting n = 2 in the recursive formula.
Thus, we have;
[tex]a_2=a_{2-1}+2(2)[/tex]
[tex]a_2=a_{1}+2(2)[/tex]
[tex]a_2=4+4[/tex]
[tex]a_2=8[/tex]
Thus, the second term of the sequence is 8.
Third term:
The third term of the sequence can be determined by substituting n = 3 in the recursive formula.
Thus, we have;
[tex]a_3=a_{3-1}+2(3)[/tex]
[tex]a_3=a_{2}+2(3)[/tex]
[tex]a_3=8+6[/tex]
[tex]a_3=14[/tex]
Thus, the third term of the sequence is 14.
Fourth term:
The fourth term of the sequence can be determined by substituting n = 4 in the recursive formula.
Thus, we have;
[tex]a_4=a_{4-1}+2(4)[/tex]
[tex]a_4=a_{3}+2(4)[/tex]
[tex]a_4=14+8[/tex]
[tex]a_4=22[/tex]
Thus, the fourth term of the sequence is 22.
Hence, the first four terms of the sequence is 4, 8, 14, 22.