Question

Find the amount of energy (Q) required to raise the temperature of the water in kilo joules (KJ).
Given mass of water m = 2kg = 2000g.
Temperature difference ΔΤ = T2 – T1 = 60 °C – 25 °C = 35 °C .
Specific heat of water = 4.18 J/g* °C .
Therefore, Q =
kilo joules.

Answer 1

Amount of energy required = 292.6 kJ

Explanation:

Amount of energy required is given by the equation ,

Q = m × C ×ΔT

where m is the mass of the water = 2000 g

C is the specific heat of water = 4.18 J/g°C

ΔT = Temperature difference = 60 - 25 = 35 °C

Applying these values in the above equation, we will get,

Q = 2000 g × 4.18 J/g°C × 35°C

  = 292600 J

When joule is divided by 1000 we will get the amount of energy in kJ.

$Q = \frac{292600}{1000} = 292.6 kJ$

So the energy required to raise the temperature of the water is 292.6 kJ.