Respuesta :
Answer:
Probability that a single student randomly chosen from all those taking the test scores 539 or higher is 0.5714.
Step-by-step explanation:
We are given that the scores of students on the SAT college entrance examinations at a certain high school had a normal distribution with mean μ = 534 and standard deviation σ = 27.3.
Let X = scores of students on the SAT college entrance examinations
SO, X ~ N([tex]\mu = 21.2,\sigma^{2} = 6.2^{2}[/tex])
The z-score probability distribution is given by ;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = mean score = 534
[tex]\sigma[/tex] = standard deviation = 27.3
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
Now, the probability that a single student randomly chosen from all those taking the test scores 539 or higher is given by = P(X [tex]\geq[/tex] 539)
P(X [tex]\geq[/tex] 539) = P( [tex]\frac{X-\mu}{\sigma}[/tex] [tex]\geq[/tex] [tex]\frac{539-534}{27.3}[/tex] ) = P(Z [tex]\geq[/tex] 0.18)
= 0.5714 {using z table}
Therefore, probability that a single student scores 539 or higher is 0.5714.
Probability that a single student randomly chosen from all those taking the test scores 539 or higher is 0.5714.