Respuesta :
Answer:
The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.
Step-by-step explanation:
Assumptions:
1. The sampling from the different discussion sections was independent and random.
2. The populations are normal with means and constant variance
[tex]H_0:[/tex] There's no variation among the discussion sections
[tex]H_1:[/tex] There's variation among the discussion sections
[tex]\alpha =0.05[/tex]
Df Sum Sq Mean sq F value Pr(>F)
Section 7 525.01 75 1.87 0.99986
Residuals 189 7584.11 40.13
Test Statistic = [tex]F= \frac{75}{40.13} =1.87[/tex]
[tex]Pr(>F) = 0.99986[/tex]
Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.
Comparing the Critical and Statistic value of F, we can conclude that there is no variation in the average scores across the groups
The Hypothesis :
[tex] H_{0} : [/tex] Average score is the same across the groups
[tex] H_{1} : [/tex] Average score varies across the groups
From the ANOVA output given, the Fstatistic = 1.87
Decison Region :
- Reject [tex] H_{0} : [/tex], if Fstatistic is greater than Fcritical
Using a F distribution table or calculator ;
Df_numerator = 7 ; df_denominator = 189
Fcritical at 5% = 2.058
Hence,
Since Fstatistic < Fcritical ; we fail to reject [tex] H_{0} [/tex]
Hence, we conclude that there is no variation in the average scores across the groups.
Learn more : https://brainly.com/question/15137933