Question

Find the coordinates of the center and the measure of the radius for a circle whose equation is (x-3)^2 + (y-7)^2=2
center = (3,7), radius = 1
center = (-3, -7), radius =4
center = (-3, -7), radius =1
center = (3,7), radius = √2

Answer 1

Answer:

fourth option

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 3)² + (y - 7)² = 2 ← is in standard form

with centre = (h, k) = (3, 7) and r² = 2 ⇒ r = $\sqrt{2}$

Answer 2

Answer:

fourth option

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 3)² + (y - 7)² = 2 ← is in standard form

with centre = (h, k) = (3, 7) and r² = 2 ⇒ r = sqre rt of 2