Answer:
Electric force, F = [tex]2.27\times 10^6\ N[/tex]
Explanation:
Given that,
In a thundercloud there may be an electric charge of 35 C near the top and −35 C near the bottom.
The separation between charges, r = 2.2 km
We need to find the magnitude of the electric force between them. We know that the formula used to find the electric force is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
k is Coulomb constant
[tex]F=\dfrac{8.98755\times 10^9\times 35^2}{(2.2\times 10^3)^2}\\\\F=2.27\times 10^6\ N[/tex]
So, the magnitude of the electric force between them is [tex]2.27\times 10^6\ N[/tex].