Answer: The amount of acetylene gas needed in the reaction is 2.00 moles
Explanation:
We are given:
Moles of water = 2.00 moles
The chemical equation for the reaction of acetylene with oxygen gas follows:
[tex]2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O[/tex]
By Stoichiometry of the reaction:
2 moles of water is produced by 2 moles of acetylene gas
So, 2.00 moles of water will be produced by = [tex]\frac{2}{2}\times 2.00=2.00mol[/tex] of acetylene gas
Hence, the amount of acetylene gas needed in the reaction is 2.00 moles