Answer:
Explanation:
According to the Kepler's third law, the square of the time period of a planet is directly proportional to the length of cube of semi major axis.
Let M is the mass of sun, m is the mass of planet and r is the radius of orbit and T is the time period of the planet around the sun. Here ω is the angular velocity of the planet around the sun.
G is the universal gravitational constant.
The centripetal force is balanced by the gravitational force between the planet and the sun.
[tex]mr\omega^{2}=\frac{GMm}{r^{2}}[/tex]
[tex]r\times \frac{4 \pi^{2}}{T^{2}}=\frac{GM}{r^{2}}[/tex]
[tex]T^{2}=\frac{4 \pi^{2}r^{3}}{GM}[/tex]
[tex]T=\sqrt \frac{4 \pi^{2}r^{3}}{GM}[/tex]