Question

According to an​ article, 36​% of adults have experienced a breakup at least once during the last 10 years. Of 9 randomly selected​ adults, find the probability that the​ number, X, who have experienced a breakup at least once during the last 10 years is

Answer 1

Title:

See the explanation.

Step-by-step explanation:

The probability that an adult will experience breakup at least once during the last ten years is $\frac{36}{100} = 0.36$.

Hence, the probability that the adult will not experience breakup is (1 - 0.36) = 0.64.

As per the given question, X is the number of adults who face breakup. From the 9 people X persons can be chosen in $^9C_X$ ways.

The probability that X persons will experience breakup is $^9C_X \times (0.36)^X \times (0.64)^{9 - X}$.