Answer:
velocity is 15.083 m/s
Explanation:
given data
length L = 1 m
Laminar to turbulent flow
xc = 0.5 m
Reynolds number Rex, c = 5 × [tex]10^{5}[/tex]
solution
we take here for 350 K
[tex]\mu[/tex] = 1.81 × [tex]10^{-5}[/tex]
and here Reynolds number Rex, is express as
Rex = [tex]\frac{\sigma \times v \times x}{\mu }[/tex] ................1
put here value at x = 0.5
5 × [tex]10^{5}[/tex] = [tex]\frac{1.2\times v \times 0.5}{1.81\times 10^{-5} }[/tex]
solve it we get
v = 15.083 m/s
so velocity is 15.083 m/s