Answer:
15116.4 V
Explanation:
B = Earth's magnetic field at the location = [tex]6.5\times 10^{-5}\ T[/tex]
L = Length of the wire = [tex]3.42\times 10^4\ m[/tex]
v = Velocity of the shuttle = [tex]6.8\times 10^8\ m/s[/tex]
The emf generated is given by
[tex]E=BLv\\\Rightarrow E=6.5\times 10^{-5}\times 3.42\times 10^{4}\times 6.8\times 10^3\\\Rightarrow E=15116.4\ V[/tex]
The motional emf generated between the ends of the wire is 15116.4 V