Answer:
Sample size, n = 289
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 0.8 grams per mile
Standard Deviation, σ = 0.17 grams per mile
We have to find the sample size such that standard deviation of the sampling distribution is 0.01 grams per mile.
Formula:
Standard error =
[tex]\dfrac{\sigma}{\sqrt{n}}[/tex]
Putting values, we get,
[tex]\dfrac{\sigma}{\sqrt{n}} = 0.01\\\\\dfrac{0.17}{\sqrt{n}} = 0.01\\\\\sqrt{n} = \dfrac{0.17}{0.01}\\\sqrt{n} = 17\\\Righatrrow n = 289[/tex]
Thus, the sample size must be 289 so that the sampling distribution have a standard deviation of 0.01 grams per mile.