Answer:
The probability that at least 1 apple is damaged in the sample of 10 is 0.6882. Therefore, the sample size is too low to determine anything with accuracy.
Step-by-step explanation:
Let X be the total of damaged apples in the sample of 10. X has binomial distribution with parameters p =0.11 and n = 10. The probability that at least 1 apple is damaged is P(X≥1). This probability can be computed using the probability complementary event, P(X≥1) = 1 - P(X=0); and
[tex]P(X=0) = {10 \choose 0} * 0.11^0*0.89^{10} = 0.89^{10} = 0.3118[/tex]
Thus, the probability that at least 1 apple is damaged is 1-0.3118 = 0,6882. The sample size is too small to determine anything, since Steven will be mistaken almost half of the time (it should be at least 30 to obtain significant results). Replacement of the apples isnt necessary because the shipment has thousands of apples and he is just picking a few, that wouldnt change the probability that an apple is damaged in a significant way. Last, but not least, a Normal approximation should not give accurate results, because the value of n is too low (n should be at the very least 20, but better if it is at least 30).