Question

xercise 15.29: At a distance of 6.00×1012 m from a star, the intensity of the radiation from the star is 14.7 W/m2. Assuming that the star radiates uniformly in all directions, what is the total power output of the star?

Answer 1

Answer:

$6.65*10^{27}W$

Explanation:

The relationship of intensity:

$I=\frac{P}{4\pi r^{2} }$

Intensity: $I=14W/m^{2}$

radius: $r=6.00*10^{12} m$

Power is unknown

Now we can apply the formula

$I=\frac{P}{4\pi r^{2} }\\P=I(4\pi r^{2})\\P=14.7(4*\pi *(6.00*10^{12} )^{2} )\\P=6.65*10^{27} W$