Question

A 61.0 cm wire carries a current of 1.00 A. The wire is formed into a single circular loop and placed in a magnetic field of intensity 1.00 T. Find the maximum torque that can act on the loop.

Answer 1

Answer:

0.029 Nm

Explanation:

We are given that

Length of wire,l=61 cm=$\frac{61}{100}=0.61 m$

1 m=100 cm

Current,I=1 A

Magnetic field intensity,B=1 T

We have to find the maximum torque that can act on the loop.

$r=\frac{l}{2\pi}=\frac{61}{2\times 3.14}=0.097 m$

Where $\pi=3.14$

Torque,$\tau=IAB=\pi r^2IB$

Substitute the values

$\tau=3.14\times (0.097)^2\times 1\times 1=0.029 Nm$