Answer:
[LiOH] = 1.99M
Explanation:
We can apply this rule of three to determine the molarity of LiOH
Molarity are the moles of solute (in this case, LiOH) that are contained in 1L of solution. Our solution's volume is 750 mL
We convert the volume to L → 750 mL . 1L / 1000mL = 0.750L
Therefore we propose:
In 0.750L we have 1.495 moles of LiOH
In 1L we may have (1 . 1.495) /0.750 = 1.99 moles
Molarity → mol/L