Answer:
3.59 m/s
Explanation:
We are given that
Mass of lineman,m=85 kg
Mass of receiver,m'=90 kg
Speed of receiver,v'=5.8 m/s
Speed of lineman,v=4.1 m/s
[tex]\theta=90^{\circ}[/tex]
We have to find the their velocity immediately after the tackle.
Initial momentum,[tex]P_i=\sqrt{p^2_1+p^2_2}=\sqrt{(85\times 4.1)^2+(90\times 5.8)^2}=627.6 kgm/s[/tex]
According to law of conservation of momentum
Initial momentum=Final momentum=[tex](m+m')V[/tex]
[tex]627.6=(85+90)V=175V[/tex]
[tex]V=\frac{627.6}{175}=3.59 m/s[/tex]