The p−toluenesulfonate derived from (R)−2−octanol and p−toluenesulfonyl chloride was allowed to react with sodium benzenethiolate (C6H5SNa). Give the structure, including stereochemistry, of the product.

Respuesta :

Answer:

A thioether is formed as product with opposite configuration.

Explanation:

  • (R)-2-octanol substitutes Cl from p-toluenesulfonyl chloride to produce p-toluenesulfonate derivative. Here stereochemistry of 2-octanol is retained as no bond breaking or bond formation takes place at chiral center.
  • [tex]C_{6}H_{5}S^{-}[/tex] gives [tex]S_{N}2[/tex] reaction with p-toluenesulfonate derivative to produce a thioether with (S) configuration. Here inversion of configuration takes place due to backside attack by [tex]C_{6}H_{5}S^{-}[/tex].
  • Structure of product has been shown below.
Ver imagen OrethaWilkison

The reaction of p−toluenesulfonate and sodium benzenethiolate occurs by SN2 mechanism hence there is inversion of configuration and the chiral center.

In these series of reactions, p−toluenesulfonate is derived from (R)−2−octanol and p−toluenesulfonyl chloride. The product is shown in the images attached.

The reaction of p−toluenesulfonate and sodium benzenethiolate occurs by SN2 mechanism hence there is inversion of configuration and the chiral center as shown in the image attached.

Learn more about streochemistry: https://brainly.com/question/953809

Ver imagen pstnonsonjoku
Ver imagen pstnonsonjoku
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