Answer:
The speed of the vehicle moving along its descent path is [tex]v=66.35 ms^{-1}[/tex].
Explanation:
It is given in the problem that a descent vehicle landing on the moon has a vertical velocity toward the surface of the moon of 37.7 m/s. At the same time, it has a horizontal velocity of 54.6 m/s.
The expression for the velocity of the vehicle moving along the descent path is as follows;
[tex]v=\sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]
Here,[tex]v_{y}[/tex] is the vertical velocity of the vehicle landing on the surface of the moon and [tex]v_{x}[/tex] is the horizontal velocity of the vehicle landing on the surface of the moon.
Put [tex]v_{x}=54.6 ms^{-1}[/tex] and [tex]v_{y}=-37.7 ms^{-1}[/tex] in the above expression.
[tex]v=\sqrt{(54.6)^{2}+(-37.7)^{2}}[/tex]
[tex]v=\sqrt{2981.1+1421.29}[/tex]
[tex]v=66.35 ms^{-1}[/tex]
Therefore, the speed of the vehicle moving along its descent path is [tex]v=66.35 ms^{-1}[/tex].