Question

can someone answer this question quickly? thanks

Ten tiles numbered 1 through 10 are placed in a bag. You randomly choose one tile. Without replacing the first tile, you randomly choose a second tile. Find the probability of choosing the 6 and then a number greater than 3. Write your answer as a fraction in simplest form.

Answer 1

Step-by-step explanation:

Let the sample space be S

S= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

$\therefore n(S) = 10$

Let A be the event of getting 6.

A = {6}

$\therefore n(A) = 1\\

P(A) = \frac{n(A)}{n(S)} = \frac{1}{10}$

Let B be the event of getting a number greater than 3.

B = {4, 5, 6, 7, 8, 9, 10}

$\therefore n(B) = 7\\

P(B) = \frac{n(B)}{n(S)} = \frac{7}{10}$