Given:
Line [tex]8 x-6 y=-4[/tex]
To find:
Slope of the perpendicular line and slope of the parallel line.
Solution:
Equation of a given line:
[tex]8 x-6 y=-4[/tex]
Subtract 8x on both sides, we get
[tex]8 x-6 y-8x=-4-8x[/tex]
[tex]-6 y=-8x-4[/tex]
Divide by -6 on both sides.
[tex]$\frac{-6 y}{-6} =\frac{-8x}{-6} -\frac{4}{-6}[/tex]
[tex]$y =\frac{4x}{3} +\frac{2}{3}[/tex]
Slope of this line is [tex]\frac{4}{3}[/tex].
If two lines are perpendicular then their slopes are negative inverse of one another.
Slope of perpendicular line = [tex]-\frac{3}{4}[/tex]
If two lines are parallel, then their slopes are equal.
Slope of perpendicular line = [tex]\frac{4}{3}[/tex]
