you are given the number of moles, from the given formula you can get the molar mass which is 12.00g/mol + 16 g/mol =28 g/mol. using the formula n=m/Mr rearrange the formula and make m subject, you thn have m=nMr therefore 7.60x 1021 mol x 28g/mol= m
m = 217268.8 g, you will notice that mol cancel out each other leaving you with g.
now convert g to litres
1 litre is equal to 1000 grams therefore
217268.8g x 1l/1000g = 217,269 litres
The volume of [tex]\rm 7.60\;\times\;10^2^1[/tex] CO molecules has been 2.82 L.
The CO has been assumed to be an ideal gas. The volume of a mole of gas at STP has been equivalent to 22.4 L.
The molar mass of CO has been 28 g/mol.
The moles of CO in given molecules has been:
[tex]\rm 6.023\;\times\;10^2^3\;molecules=1\;mol\\7.60\;\times\;10^2^1\;molecules=\dfrac{1}{6.023\;\times\;10^2^3}\;\times\;7.60\;\times\;10^2^1\;mol \\7.60\;\times\;10^2^1\;molecules=0.012\;mol[/tex]
The moles of CO has been 0.012 mol.
The volume of CO has been computed as:
[tex]\rm 1\;mol=22.4\;L\\0.012\;mol=22.4\;\times\;0.012\;L\\0.012\;mol=2.82\;L[/tex]
The volume of [tex]\rm 7.60\;\times\;10^2^1[/tex] CO molecules has been 2.82 L.
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