Answer:
Option B
Step-by-step explanation:
Using the law of logarithms
[tex]n log x= log x^{n}[/tex]
Therefore, since all the logs are to the same base, I will assume the base.
Also, when the bases are the same
log y+ log x= log (x+y)
[tex]\frac {1}{2}(log 4+ log 16)=log 4^{0.5}+log 16^{0.5}=log 2+log 4=log 6[/tex]
Now log 6-log 2= log (6-2)= log 4
Therefore, option B is correct
