Answer:
Step-by-step explanation:
1/8x^-2y^-6
From the law of indices a^-1=1/a^1
Adopting these
(8x^-2y^-6)^-1
8^-1(x^-2)^-1(y^-6)^-1
8 = 2x2x2=2^3
(2^3)^-1(x^-2)^-1(y^-6)^-1
(2^-3)(x^-2-1)(y^-6-1)
(2^-3)(x^-3)(y^-7)
(3×)^-3y^4/-x^2y^-6
3^-3x^-3y^4/-x^2y^-6
From the law of indices / division means - subtraction
3^-3x^-3y^4/-x^2y^-6 = 3^-3x^-3^-2y^4^-6= 3^-3x^-5y^4+(-6)
3^-3x^-5y^-2
