Answer:
The event space for rolling a sum of 9 with two dice is: {(3,6), (4,5), (5,4), (6,3)}
And the number of elements in event space is 4
Step-by-step explanation:
When two dices are rolled, the sample space is:
S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6),(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
Let A be the event that the sum of the outcomes of dice is 9
The event space will be:
A = {(3,6), (4,5), (5,4), (6,3)}
The number of elements in the event space are 4 so
[tex]n(A) = 4[/tex]
Hence,
The event space for rolling a sum of 9 with two dice is: {(3,6), (4,5), (5,4), (6,3)}
And the number of elements in event space is 4