Answer:
see the explanation
Step-by-step explanation:
we know that
The end behavior of a polynomial function is the behavior of the graph of f(x) as x approaches positive infinity or negative infinity.
The degree and the leading coefficient of a polynomial function determine the end behavior of the graph
In this problem
we have
[tex]f)x)=x^2+4x+3[/tex]
Is a vertical parabola open upward (the vertex is a minimum)
The degree of the function is even (2) and the leading coefficient is positive.
So,
the end behavior is:
f(x)→+∞, as x→−∞
f(x)→+∞, as x→+∞