Question

One angle of a triangle measures $10degrees$ more than the second. The measure of the third angle is twice the sum of the first two angles. What is the measure of each angle?

Answer 1

Answer:

$One\ angle: 35^o\\Second\ angle: 25^o\\Third\ angle: 120^o$

Step-by-step explanation:

Let

x ----> the measure of one angle of the triangle

y ---> the measure of the second angle

z ----> the measure of the third angle

we know that

The sum of the measure of the interior angles in any triangle must be equal to 180 degrees

$x+y+z=180^o$ -----> equation A

One angle of a triangle measures  10 degrees more than the second

$x=y+10$ ----> equation B

The measure of the third angle is twice the sum of the first two angles

$z=2(x+y)$ ---> equation C

substitute equation B in equation C

$z=2(y+10+y)$

$z=4y+20$ ----> equation D

substitute equation D and equation B in equation A

$(y+10)+y+(4y+20)=180^o$

solve for y

$6y=180-30\\6y=150\\y=25^o$

Find the value of x

$x=25+10=35^o$

Find the value of z

$z=4(25)+20=120^o$

therefore

$One\ angle: 35^o\\Second\ angle: 25^o\\Third\ angle: 120^o$