Answer:
1.32g
Explanation:
Given parameters:
Mass of HF = 4.65g
Unknown:
Mass of NH₃ = ?
Solution:
We need to know the reaction equation first of all. The reaction that will produce HF involves;
2NH₃ + 5F₂ → N₂F₄ + 6HF
Now that we know the reaction equation;
Find the number of moles of the HF;
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of HF = 1 + 19 = 20g/mol
Number of moles = [tex]\frac{4.65}{20}[/tex] = 0.23mole
From the balanced reaction equation;
6 moles of HF is produced from 2 moles of NH₃
0.23 moles of HF will be produced from [tex]\frac{0.23 x 2}{6}[/tex] = 0.08moles
Now we find the mass of NH₃
Mass of NH₃ = number of moles x molar mass
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
Mass of NH₃ = 0.08 x 17 = 1.32g
