The probability that both grab oranges would be = [tex]\frac{1}{36}[/tex]
Step-by-step explanation:
Given,
A bowl contains,
Apples = a = 5
Oranges = o = 2
bananas = b = 2
Total fruits in bowl = x = a + o + b = 5 + 2 + 2 = 9
Now, Christian and Aaron come home from school and randomly grab one fruit each.
The probability of first selecting orange would be = [tex]\frac{o}{b} = \frac{2}{9}[/tex]
Now, the oranges left would be 2 - 1 = 1
and total fruits would be = 9 - 1 = 8
Hence, the probability of selecting second orange would be = [tex]\frac{1}{8}[/tex]
Therefore, the probability that both grab oranges would be = [tex]\frac{1}{8} * \frac{2}{9} = \frac{1}{36}[/tex]
