Respuesta :
The solutions are x=0 and y= -2, if the given equations are [tex]-20x+4y=-8[/tex] and [tex]-20x-2y=4[/tex].
Step-by-step explanation:
The given is,
[tex]-20x+4y=-8[/tex]...............................(1)
[tex]-20x-2y=4[/tex].................................(2)
Step:1
To find the values of x and y, we subtract the equation (1) and (2)
[tex]-20x+4y=-8[/tex]
[tex]-20x-2y=4[/tex]
( - )
Subtraction of the Eqn (1) and (2) becomes,
[tex](-20x+20x)+(4y+2y)=(-8-4)[/tex]
[tex]6y=-12[/tex]
[tex]y =-\frac{12}{6}[/tex]
[tex]y = -2[/tex]
Substitute the value of y in Equation (2),
[tex]-20x-2y=4[/tex]
[tex]-20x-(2)(-2)=4[/tex]
[tex]-20x+4=-4[/tex]
[tex]-20x=4-4[/tex]
[tex]-20x=0[/tex]
x = 0
Step:2
Check for solution,
[tex]-20x+4y=-8[/tex]
Substitute the values of X and y,
[tex](-20)(0)+(4)(-2)=-8[/tex]
[tex]0-8=-8[/tex]
-8 = -8
Both sides are equal so the values of x = 0 and y = -2 are equal.
Result:
The solutions are x=0 and y= -2, if the given equations are [tex]-20x+4y=-8[/tex] and [tex]-20x-2y=4[/tex].
