DELTA H FOR THE REACTION OF SULFUR DIOXIDE WITH OXYGEN IS -197.8 KJ.
Explanation:
The letter "H" represents the enthalpy of a system. Enthalpy refers to the sum of the internal energy of a system plus the product of the system's pressure and volume. The delta symbol is used to represent change. Therefore, delta H represents the change in enthalpy of a system in a reaction.
∆H = ∆Hf (products) - ∆Hf(reactants)
∆H = 2X ∆Hf(SO3) - [ 2 X ∆Hf(SO2) + ∆Hf(O2) ]
∆H = 2 X -395.7 - [ 2 X -296.8 + 0 ]
elements in their standard state has zero ∆Hf
∆H = -791.4 + 593.6 = -197.8 kj
so answer is –197.8 kJ
