Question

What is the length of the diagonal of a rectangle whose height is 8 cm and whose base is 15 cm?

Answer 1

For this case we have by definition:

The diagonal of a rectangle can be found using the Pythagorean theorem (By drawing the diagonal, two rectangular triangles are formed):

$d = \sqrt {h ^ 2 + b ^ 2}$

Where:

h: Is the height of the rectangle

b: It is the base of the rectangle

According to the data we have to:

$h = 8 \ cm\\b = 15 \ cm$

Substituting the data:

$d = \sqrt {8 ^ 2 + 15 ^ 2}\\d = \sqrt {64 + 225}\\d = \sqrt {289}\\d = 17$

Thus, the diagonal of the rectangle is$17 \ cm$

Answer:

$17 \ cm$