Answer:
[tex]14.8+2W\leq 23[/tex]
The value of the width must be less than or equal to 4.1 meters
Step-by-step explanation:
we know that
The perimeter of the rectangular section is given by
[tex]P=2L+2W[/tex]
we have
[tex]L=7.4\ m[/tex]
substitute
[tex]P=2(7.4)+2W[/tex]
[tex]P=14.8+2W[/tex]
Remember that
The manager can use no more than 23 m of rope
so
The perimeter must be less than or equal to 23 m
[tex]14.8+2W\leq 23[/tex]
solve for W
subtract 14.8 both sides
[tex]2W\leq 23-14.8[/tex]
[tex]2W\leq 8.2[/tex]
divide by 2 both sides
[tex]W\leq 4.1\ m[/tex]
The value of the width must be less than or equal to 4.1 meters